In Melde's experiment,the string vibrates in | vedclass

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(C) The frequency of vibration of a string is given by $n = \frac{p}{2l} \sqrt{\frac{T}{m}}$,where $p$ is the number of loops,$l$ is the length,$T$ is

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$0.036 \,kg \,wt$

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(C) The frequency of vibration of a string is given by $n = \frac{p}{2l} \sqrt{\frac{T}{m}}$,where $p$ is the number of loops,$l$ is the length,$T$ is the tension,and $m$ is the mass per unit length.Since $n$,$l$,and $m$ are constant,we have $p \propto \frac{1}{\sqrt{T}}$,which implies $p_1 \sqrt{T_1} = p_2 \sqrt{T_2}$.Given $p_1 = 4$ and $T_1 = (50 + 15) \,g = 65 \,g$.For $p_2 = 6$,we have $4 \sqrt{65} = 6 \sqrt{T_2}$.Squaring both sides: $16 	imes 65 = 36 	imes T_2$.$T_2 = \frac{16 	imes 65}{36} = \frac{4 	imes 65}{9} \approx 28.89 \,g$.The weight to be removed is $\Delta T = T_1 - T_2 = 65 - 28.89 = 36.11 \,g \approx 36 \,g$.Converting to $kg$,we get $36 \,g = 0.036 \,kg \,wt$.

In Melde's experiment,the string vibrates in $4$ loops when a $50 \,g$ weight is placed in the pan of weight $15 \,g$. To make the string vibrate in $6$ loops,the weight that has to be removed from the pan is:

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