In non-cyclic photophosphorylation:

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(C) In non-cyclic photophosphorylation,both $PS-II$ and $PS-I$ are involved. The electrons released from $PS-I$ are accepted by $NADP^+$ to form $NADP

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$NADP$ reductase activity requires $H^+$ from stroma

Vedclass · Answer

(C) In non-cyclic photophosphorylation,both $PS-II$ and $PS-I$ are involved. The electrons released from $PS-I$ are accepted by $NADP^+$ to form $NADPH$. The enzyme $NADP$ reductase is located on the outer side of the thylakoid membrane. It utilizes $H^+$ ions from the stroma to reduce $NADP^+$ into $NADPH + H^+$. Thus,the reaction is $NADP^+ + 2H^+ + 2e^- \longrightarrow NADPH + H^+$.

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