In order to complete the reaction 1-Pentyne x | vedclass

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(A) Step $1$: $1-Pentyne$ $(CH_3CH_2CH_2C \equiv CH)$ reacts with $NaNH_2$ to form the acetylide ion $(CH_3CH_2CH_2C \equiv C^- Na^+)$.Step $2$: This

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(A) Step $1$: $1-Pentyne$ $(CH_3CH_2CH_2C \equiv CH)$ reacts with $NaNH_2$ to form the acetylide ion $(CH_3CH_2CH_2C \equiv C^- Na^+)$.Step $2$: This nucleophile reacts with $n-propyl \ bromide$ $(CH_3CH_2CH_2Br)$ via $S_N2$ mechanism to yield $4-Octyne$ $(CH_3CH_2CH_2C \equiv CCH_2CH_2CH_3)$.Step $3$: To reduce an internal alkyne to a $cis-alkene$,we use $H_2$ with a poisoned catalyst like $Lindlar \ catalyst$ ($Pd/CaCO_3/PbO$ or $Pd/BaSO_4$).Thus,$a$ is $NaNH_2; CH_3CH_2CH_2Br$ and $b$ is $H_2, (1 \ mole) 	ext{ Lindlar catalyst}$.

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