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(B) The time period of a pendulum clock is given by $T = 2\pi \sqrt{l/g}$. In an orbiting satellite,the astronaut experiences weightlessness,which mea

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$A$ watch having a main spring to keep it going

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(B) The time period of a pendulum clock is given by $T = 2\pi \sqrt{l/g}$. In an orbiting satellite,the astronaut experiences weightlessness,which means the effective acceleration due to gravity $g$ is $0$. As $g 	o 0$,$T 	o \infty$,so a pendulum clock will not work.However,a watch that uses a main spring to keep it going relies on the elastic properties of the spring and the oscillation of a balance wheel,which are independent of the gravitational field. Therefore,it will function correctly in a satellite.

In order to find time,the astronaut orbiting in an earth satellite should use

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