In a potassium atom,the electronic energy lev | vedclass

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Question

(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of its principal quantum number $(n)$ and azimuthal quantum number

Vedclass · Accepted Answer

$4s < 3d$

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(C) According to the $(n+l)$ rule,the energy of an orbital is determined by the sum of its principal quantum number $(n)$ and azimuthal quantum number $(l)$.For $4s$ orbital: $n = 4, l = 0$,so $(n+l) = 4 + 0 = 4$.For $3d$ orbital: $n = 3, l = 2$,so $(n+l) = 3 + 2 = 5$.Since the $(n+l)$ value for $4s$ is less than that of $3d$,the $4s$ orbital has lower energy than the $3d$ orbital. Thus,$4s < 3d$.

In a potassium atom,the electronic energy levels are in the following order:

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