In a potentiometer,a balance point is obtained when:
- AThe $e.m.f.$ of the battery becomes equal to the $e.m.f.$ of the experimental cell.
- BThe $p.d.$ of the wire between the $+ve$ end and the jockey becomes equal to the $e.m.f.$ of the experimental cell.
- CThe $p.d.$ of the wire between the $+ve$ point and the jockey becomes equal to the $e.m.f.$ of the battery.
- DThe $p.d.$ across the potentiometer wire becomes equal to the $e.m.f.$ of the battery.
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Similar Questions
The adjoining figure shows the connections of a potentiometer experiment to determine the internal resistance of a Leclanché cell. When the cell is on open circuit,the balancing length of the potentiometer wire is $3.4 \, m$,and on closing the key $K_2$,the balancing length becomes $1.7 \, m$. If the resistance $R$ through which current is drawn is $10 \, \Omega$,then the internal resistance of the cell is .............. $\Omega$.
Medium
View SolutionAn ideal battery of $4\, V$ and resistance $R$ are connected in series in the primary circuit of a potentiometer of length $1\, m$ and resistance $5\,\Omega$. The value of $R$,to give a potential difference of $5\, mV$ across $10\, cm$ of potentiometer wire,is: ................ $\Omega$
The sliding contact of a potentiometer is in the middle of the potentiometer wire having a total resistance $R_p = 1 \Omega$,as shown in the figure. An external resistance of $R_e = 2 \Omega$ is connected via the sliding contact. Find the total current drawn from the $0.9 \text{ V}$ battery. (in $\text{ A}$)
DifficultJEE MAIN 2025
View SolutionIn the circuit shown, a four-wire potentiometer is made of a $400\, cm$ long wire, which extends between $A$ and $B$. The resistance per unit length of the potentiometer wire is $r = 0.01\, \Omega /cm$. If an ideal voltmeter is connected as shown with jockey $J$ at $50\, cm$ from end $A$, the expected reading of the voltmeter will be: ............... $V$
For the measurement of potential difference,a potentiometer is preferred in comparison to a voltmeter because
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