In a pure inductive circuit, the curve betwee | vedclass

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(C) The inductive reactance $X_L$ of an inductor is given by the formula: $X_L = 2\pi fL$, where $f$ is the frequency and $L$ is the inductance.Taking

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(C) The inductive reactance $X_L$ of an inductor is given by the formula: $X_L = 2\pi fL$, where $f$ is the frequency and $L$ is the inductance.Taking the reciprocal of both sides, we get: $\frac{1}{X_L} = \frac{1}{2\pi fL}$.This can be rewritten as: $\frac{1}{X_L} = \left( \frac{1}{2\pi L} \right) \cdot \frac{1}{f}$.Let $y = \frac{1}{X_L}$ and $x = f$. Then the equation becomes $y = \frac{k}{x}$, where $k = \frac{1}{2\pi L}$ is a constant.This is the equation of a rectangular hyperbola. Therefore, the graph between $\frac{1}{X_L}$ and $f$ is a rectangular hyperbola.

In a pure inductive circuit, the curve between frequency $f$ and the reciprocal of inductive reactance $1/X_L$ is:

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