In a series $LR$ circuit,$X_L = 3R$. Now,a capacitor with $X_C = R$ is added in series. What is the ratio of the new power factor to the old power factor?

Which of the following components of an $L-C-R$ circuit,with an $AC$ supply,dissipates energy?

$A$ series $LCR$ circuit containing an $AC$ source of $100 \ V$ has an inductor and a capacitor of reactances $24 \ \Omega$ and $16 \ \Omega$ respectively. If a resistance of $6 \ \Omega$ is connected in series,then the potential difference across the series combination of inductor and capacitor only is (in $V$)

$A$ series $LR$ circuit is connected to an ac source of frequency $\omega$ and the inductive reactance is equal to $2R$. $A$ capacitance of capacitive reactance equal to $R$ is added in series with $L$ and $R$. The ratio of the new power factor to the old one is

In the adjoining figure,the impedance of the circuit will be $... \Omega$.

An $LCR$ series circuit with $R = 100\,\Omega$ is connected to a $200\,V, 50\,Hz$ $a.c.$ source. When only the capacitance is removed,the current lags the voltage by $60^o$. When only the inductance is removed,the current leads the voltage by $60^o$. The current in the circuit is.....$A$