In the adjoining figure,four capacitors are s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The two $4\,\mu F$ capacitors are in parallel,so their equivalent capacitance is $C_p = 4\,\mu F + 4\,\mu F = 8\,\mu F$.$2$. Now,the circuit

Vedclass · Accepted Answer

$580\,\mu C;\;145\;V$

Vedclass · Answer

(D) $1$. The two $4\,\mu F$ capacitors are in parallel,so their equivalent capacitance is $C_p = 4\,\mu F + 4\,\mu F = 8\,\mu F$.$2$. Now,the circuit consists of three capacitors in series: $20\,\mu F$,$8\,\mu F$ (the parallel combination),and $12\,\mu F$.$3$. The equivalent capacitance $C_{eq}$ is given by $\frac{1}{C_{eq}} = \frac{1}{20} + \frac{1}{8} + \frac{1}{12} = \frac{6 + 15 + 10}{120} = \frac{31}{120}\,\mu F^{-1}$,so $C_{eq} = \frac{120}{31}\,\mu F$.$4$. The total charge $Q$ supplied by the $300\,V$ source is $Q = C_{eq} 	imes V = \frac{120}{31} 	imes 300 = \frac{36000}{31} \approx 1161.29\,\mu C$.$5$. Since the capacitors are in series,the same charge $Q$ flows through each branch. The charge $Q$ splits equally between the two parallel $4\,\mu F$ capacitors because they have equal capacitance.$6$. Charge on each $4\,\mu F$ capacitor is $q = \frac{Q}{2} = \frac{1161.29}{2} \approx 580.6\,\mu C$.$7$. The potential difference across the $4\,\mu F$ capacitor is $V' = \frac{q}{C} = \frac{580.6}{4} \approx 145.15\,V$. The closest option is $D$.

In the adjoining figure,four capacitors are shown with their respective capacities and the $P.D.$ applied. The charge and the $P.D.$ across the $4\,\mu F$ capacitor will be

Similar Questions

The potential difference between the points $P$ and $Q$ in the adjoining circuit will be :-

Two capacitors $C_1 = 2\,\mu F$ and $C_2 = 6\,\mu F$ in series are connected in parallel to a third capacitor $C_3 = 4\,\mu F$. This arrangement is then connected to a battery of $e.m.f. = 2\,V$,as shown in the figure. How much energy is lost by the battery in charging the capacitors?

The charge on the $4\,\mu F$ capacitor in the given circuit is .... in $\mu C$.

$A$ fully charged capacitor has a capacitance $C$. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $s$ and mass $m$. If the temperature of the block is raised by $\Delta T$,the potential difference $V$ across the capacitor is

$A$ capacitor of capacitance $C$ is initially charged to a potential difference of $V$ $volt$. Now it is connected to a battery of $2V$ with opposite polarity. The ratio of heat generated to the final energy stored in the capacitor will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module