In the case of a conical pendulum,if T is the | vedclass

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(A) In a conical pendulum,the bob moves in a horizontal circle. The forces acting on the bob are:$1$. The tension $T$ in the string,acting along the s

Vedclass · Accepted Answer

$T \sin 	heta$

Vedclass · Answer

(A) In a conical pendulum,the bob moves in a horizontal circle. The forces acting on the bob are:$1$. The tension $T$ in the string,acting along the string towards the point of suspension.$2$. The weight $mg$ of the bob,acting vertically downwards.Resolving the tension $T$ into two rectangular components:- The vertical component $T \cos 	heta$ balances the weight of the bob $(T \cos 	heta = mg)$.- The horizontal component $T \sin 	heta$ provides the necessary centripetal force required for circular motion $(T \sin 	heta = \frac{mv^2}{r})$.In the rotating frame of reference (non-inertial frame),the centrifugal force acts outwards,which is balanced by the horizontal component of the tension. Therefore,the component of tension that balances the centrifugal force is $T \sin 	heta$.

In the case of a conical pendulum,if $T$ is the tension in the string and $\theta$ is the semi-vertical angle of the cone,then the component of tension which balances the centrifugal force in the equilibrium position is

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