In the case of forward biasing of a $p-n$ junction diode,which one of the following figures correctly depicts the direction of conventional current (indicated by an arrow mark)?

Assuming in forward bias condition there is a voltage drop of $0.7 \text{ V}$ across a silicon diode, the current through diode $D_1$ in the circuit is . . . . . . $\text{mA}$. (Assume all diodes in the given circuit are identical)

In the middle of the depletion layer of a reverse-biased $PN$ junction,the

The energy of a photon in a monochromatic light of wavelength $621 \ nm$ matches with the band gap of a semiconducting material. Then the minimum energy required to create an electron-hole pair from the semiconductor is
[Take $hc = 1242 \ eV-nm$,where $h$ is Planck's constant and $c$ is speed of light in vacuum] (in $eV$)

The voltage $V_0$ in the network shown is

In a semiconductor diode,the reverse biased current is due to the drift of free electrons and holes caused by: