In the case of substituted aniline,the group | vedclass

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(D) The basic strength of aniline is determined by the availability of the lone pair of electrons on the nitrogen atom. Electron-withdrawing groups $(

Vedclass · Accepted Answer

$-C_6H_5$

Vedclass · Answer

(D) The basic strength of aniline is determined by the availability of the lone pair of electrons on the nitrogen atom. Electron-withdrawing groups $(EWG)$ decrease the electron density on the nitrogen atom,thereby decreasing the basic strength. Among the given options,$-OCH_3$,$-CH_3$,and $-NH_2$ are electron-donating groups $(EDG)$ due to their $+M$ or $+I$ effects,which increase the basic strength. $-C_6H_5$ (phenyl group) acts as an electron-withdrawing group due to its $-I$ effect and resonance,thus decreasing the basic strength of aniline.

In the case of substituted aniline,the group which decreases the basic strength is

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