In the chemical reaction given above,A and B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence is as follows:$1$. The first step is the reduction of benzene diazonium chloride to benzene. This is achieved using hypophos

Vedclass · Accepted Answer

$H_3PO_2$ and $CH_3CH_2Cl$

Vedclass · Answer

(B) The reaction sequence is as follows:$1$. The first step is the reduction of benzene diazonium chloride to benzene. This is achieved using hypophosphorous acid $(H_3PO_2)$ and water $(H_2O)$. Thus,$A = H_3PO_2$.$2$. The second step is the Friedel-Crafts alkylation of benzene to form ethylbenzene. This requires an alkyl halide,specifically ethyl chloride $(CH_3CH_2Cl)$,in the presence of an anhydrous Lewis acid catalyst like $AlCl_3$. Thus,$B = CH_3CH_2Cl$.Therefore,$A$ is $H_3PO_2$ and $B$ is $CH_3CH_2Cl$.

In the chemical reaction given above,$A$ and $B$ respectively are:

Similar Questions

Which of the following is the strongest base?

What is obtained upon the reduction of $t$-butyl isocyanide?

Acetic acid on heating with $NH_3$ forms $A$. When $A$ reacts with $LiAlH_4$ followed by hydrolysis,it gives $B$. When $B$ is heated with chloroform in $KOH$ medium,it gives $C$. What are $B$ and $C$ respectively?

The basic character of amines can be explained by which of the following theories?

Identify product $D$ in the following reaction sequence:
$CH_3-C(CH_3)_2-CH_2-CH_2-OH$ $\xrightarrow[H_2O, \text{heat}]{K_2Cr_2O_7, H_2SO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{2(CH_3)_2NH} C$ $\xrightarrow[2. H_2O]{1. LiAlH_4, \text{diethyl ether}} D$

Vedclass Test Series

Exam Paper Generator

Online Exam Module