In the circuit diagram,the heat produced in r | vedclass

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(B) The current $I$ splits into $I_1$ and $I_2$ through the parallel resistors $R$ and $2R$. Using the current divider rule:$I_1 = I 	imes \frac{2R}{

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$8: 4: 27$

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(B) The current $I$ splits into $I_1$ and $I_2$ through the parallel resistors $R$ and $2R$. Using the current divider rule:$I_1 = I 	imes \frac{2R}{R + 2R} = \frac{2I}{3}$$I_2 = I 	imes \frac{R}{R + 2R} = \frac{I}{3}$The heat produced in a resistor is given by $H = I^2 R t$. Assuming time $t$ is the same for all:$H_1 = I_1^2 R = \left(\frac{2I}{3}ight)^2 R = \frac{4I^2 R}{9}$$H_2 = I_2^2 (2R) = \left(\frac{I}{3}ight)^2 (2R) = \frac{2I^2 R}{9}$For the resistor $1.5R$,the total current $I$ flows through it:$H_3 = I^2 (1.5R) = 1.5 I^2 R = \frac{13.5 I^2 R}{9}$The ratio $H_1 : H_2 : H_3 = \frac{4}{9} : \frac{2}{9} : \frac{13.5}{9} = 4 : 2 : 13.5 = 8 : 4 : 27$.

In the circuit diagram,the heat produced in resistors $R$,$2R$,and $1.5R$ are in the ratio of:

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