In the circuit given here,the potentials at points $A$,$B$,and $C$ are $70 \,V$,$0 \,V$,and $10 \,V$ respectively. Then:

  • A
    the point $D$ will be at a potential of $60 \,V$
  • B
    the point $D$ will be at a potential of $20 \,V$
  • C
    currents in the paths $AD$,$DB$ and $DC$ are in the ratio of $3: 2: 1$
  • D
    currents in the paths $AD$,$DB$ and $DC$ are in the ratio of $1: 2: 3$

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