In the circuit shown,P ne R. The reading of t | vedclass

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(A) The reading of the galvanometer remains the same whether switch $S$ is open or closed. This implies that the potential difference across the switc

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$I_R = I_G$

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(A) The reading of the galvanometer remains the same whether switch $S$ is open or closed. This implies that the potential difference across the switch $S$ is zero,or that no current flows through the switch when it is closed. If no current flows through the switch,the branch containing $R$ and the branch containing the galvanometer $G$ effectively act as a single series circuit path between the nodes. Therefore,the same current must flow through both $R$ and $G$. Thus,$I_R = I_G$.

In the circuit shown,$P \ne R$. The reading of the galvanometer is the same with switch $S$ open or closed. Then:

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