In the circuit shown below, C_1 = 10 , mu F, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the potential at the junction between the two capacitor blocks be $V_m$. Let the potential at $X$ be $V_X$ and at $Y$ be $V_Y$. Given $C_1 = 1

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) Let the potential at the junction between the two capacitor blocks be $V_m$. Let the potential at $X$ be $V_X$ and at $Y$ be $V_Y$. Given $C_1 = 10 \, \mu F$, $C_2 = 20 \, \mu F$, $C_3 = 20 \, \mu F$, and $C_4 = 40 \, \mu F$. Charge on $C_1$ is $q_1 = 20 \, \mu C$. Potential difference across $C_1$ is $V_1 = \frac{q_1}{C_1} = \frac{20 \, \mu C}{10 \, \mu F} = 2 \, V$. Since $C_1$ and $C_2$ are in parallel, the potential difference across $C_2$ is also $2 \, V$. Charge on $C_2$ is $q_2 = C_2 V_1 = 20 \, \mu F 	imes 2 \, V = 40 \, \mu C$. The total charge entering the junction from the left side is $q_1 + q_2 = 20 \, \mu C + 40 \, \mu C = 60 \, \mu C$. This total charge must be distributed among $C_3$ and $C_4$ in series with the first block. Since $C_3$ and $C_4$ are in parallel, the total charge $60 \, \mu C$ is shared between them. The equivalent capacitance of the second block is $C_{34} = C_3 + C_4 = 20 \, \mu F + 40 \, \mu F = 60 \, \mu F$. The potential difference across the second block is $V_2 = \frac{q_{total}}{C_{34}} = \frac{60 \, \mu C}{60 \, \mu F} = 1 \, V$. The total potential difference between $X$ and $Y$ is $V_{XY} = V_1 + V_2 = 2 \, V + 1 \, V = 3 \, V$.

In the circuit shown below, $C_1 = 10 \, \mu F$, $C_2 = C_3 = 20 \, \mu F$, and $C_4 = 40 \, \mu F$. If the charge on $C_1$ is $20 \, \mu C$, then the potential difference between $X$ and $Y$ is ......... $V$.

Similar Questions

$27$ identical drops are charged at $22 \ V$ each. They combine to form a bigger drop. The potential of the bigger drop will be............ $V$.

The potential difference that must be applied across the series and parallel combination of $4$ identical capacitors is such that the energy stored in them becomes the same. The ratio of potential difference in series to parallel combination is

Plates $A$ and $B$ constitute an isolated,charged parallel-plate capacitor. The inner surfaces ($I$ and $IV$) of $A$ and $B$ have charges $+Q$ and $-Q$ respectively. $A$ third plate $C$ with charge $+Q$ is now introduced midway between $A$ and $B$. Which of the following statements is not correct?

Seven capacitors,each of capacity $2\,\mu F$,are to be connected to have a total capacity of $\frac{10}{11}\,\mu F$. Which of the following figures shows the correct arrangement?

See the diagram. The area of each plate is $2.0 \,m^{2}$ and $d=2 \times 10^{-3} \,m$. $A$ charge of $8.85 \times 10^{-8} \,C$ is given to plate $Q$. Then the potential of $Q$ becomes (in $\,V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module