In the circuit shown in the figure, neglecting the source resistance, the voltmeter and ammeter readings respectively are

  • A
    $0 \, V, 8 \, A$
  • B
    $150 \, V, 3 \, A$
  • C
    $150 \, V, 6 \, A$
  • D
    $0 \, V, 3 \, A$

Explore More

Similar Questions

Match List-$I$ with List-$II$ and choose the correct answer from the options given below:
List-$I$List-$II$
$A$. Purely capacitive circuit$I$. $I$ leads $V$ by $90^{\circ}$
$B$. Purely inductive circuit$II$. $I$ and $V$ are in phase
$C$. $LCR$ series at resonance$III$. $V$ leads $I$ by angle $\theta$
$D$. $LCR$ series circuit$IV$. $V$ leads $I$ by $90^{\circ}$

Mark the incorrect statement.

$A$ resistor of resistance $R$ and an inductor of inductive reactance $R$ are connected in series to an $AC$ source. $A$ capacitor of capacitive reactance $2R$ is then connected in series with $L$ and $R$. The ratio of the power factors of the $LR$ and $LCR$ circuits is:

An alternating power supply of $220 \,V$ is applied across a series circuit of resistance $10 \sqrt{3} \,\Omega$,capacitive reactance $40 \,\Omega$,and inductive reactance $30 \,\Omega$. The respective currents in the circuit for zero and infinite frequencies are

There is a $100\,\Omega$ resistance in an $L-C-R$ $AC$ circuit. An $AC$ $emf$ of $200\,V$ and $\omega = 300\,rad/s$ is applied to this circuit. When only the capacitor is removed,the current lags the voltage by $60^o$. When only the inductor is removed,the current leads the voltage by $60^o$. The current in this $L-C-R$ circuit will be.....$A$

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo