In the circuit shown in the figure,$P \neq R$. The reading of the galvanometer remains the same with switch $S$ open or closed. Then

  • A
    $I_{Q}=I_{G}$
  • B
    $I_{Q}=I_{R}$
  • C
    $I_{R}=I_{G}$
  • D
    $I_P=I_G$

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