In the circuit shown in the figure below,whic | vedclass

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Question

(A) $1$. The circuit contains two batteries of $10\,V$ and $20\,V$ in series,and resistors of $7.5\,\Omega$,$0.5\,\Omega$,$1\,\Omega$,and $1\,\Omega$.

Vedclass · Accepted Answer

The potential at $S$ is zero

Vedclass · Answer

(A) $1$. The circuit contains two batteries of $10\,V$ and $20\,V$ in series,and resistors of $7.5\,\Omega$,$0.5\,\Omega$,$1\,\Omega$,and $1\,\Omega$.
$2$. The net electromotive force $(EMF)$ is $E_{net} = 20\,V - 10\,V = 10\,V$.
$3$. The total resistance of the circuit is $R_{total} = 7.5\,\Omega + 0.5\,\Omega + 1\,\Omega + 1\,\Omega = 10\,\Omega$.
$4$. The current in the circuit is $I = E_{net} / R_{total} = 10\,V / 10\,\Omega = 1\,A$.
$5$. Point $G$ is grounded,so $V_G = 0\,V$. Since $S$ and $R$ are connected to $G$ by ideal wires,$V_S = 0\,V$ and $V_R = 0\,V$.
$6$. Moving from $R$ to $Q$ through the $1\,\Omega$ resistor in the direction opposite to the current,$V_Q = V_R - I 	imes 1\,\Omega = 0 - 1\,A 	imes 1\,\Omega = -1\,V$.
$7$. Moving from $S$ to $P$ through the $7.5\,\Omega$ resistor in the direction of the current,$V_P = V_S - I 	imes 7.5\,\Omega = 0 - 1\,A 	imes 7.5\,\Omega = -7.5\,V$.
$8$. Comparing these results with the options,statement $A$ is correct $(V_P = -7.5\,V)$,statement $B$ is correct $(V_Q = -1\,V)$,statement $C$ is correct $(V_R = 0\,V)$,and statement $D$ is correct $(V_S = 0\,V)$.
$9$. Re-evaluating the question,it asks for the incorrect statement. Based on the calculation,all statements provided are actually correct. However,if we must choose,there might be a typo in the question's options. Given the standard interpretation,all listed potentials are correct.

In the circuit shown in the figure below,which of the following statements is incorrect?

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