In the context of accuracy of measurement and | vedclass

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(C) Statement $(1)$ is correct because accuracy is related to the number of significant figures and the precision of the measurement. $50.14 \, cm$ ha

Vedclass · Accepted Answer

Both are correct

Vedclass · Answer

(C) Statement $(1)$ is correct because accuracy is related to the number of significant figures and the precision of the measurement. $50.14 \, cm$ has $4$ significant figures,while $0.00025 \, A$ has only $2$ significant figures. Thus,the first measurement is more accurate.Statement $(2)$ is correct because when adding quantities with different units,we must consider the precision. $478 \, km = 478000 \, m$. Adding $397 \, m$ gives $478397 \, m$. However,in terms of significant figures and precision,the result is limited by the least precise measurement. Since $478 \, km$ has precision up to the units place $(1 \, km)$,the addition of $397 \, m$ $(0.397 \, km)$ is insignificant relative to the scale of $478 \, km$. Thus,the total distance is rounded to $478 \, km$.

List-$I$	List-$II$
$A$. Spring constant	$1$. $M^1L^2T^{-2}$
$B$. Pascal	$2$. $M^0L^0T^{-1}$
$C$. Hertz	$3$. $M^1L^0T^{-2}$
$D$. Joule	$4$. $M^1L^{-1}T^{-2}$

Similar Questions

The physical quantities that have the same dimensions are:

Match List-$I$ with List-$II$ and select the correct answer.

List-$I$ List-$II$

$A$. Spring constant $1$. $M^1L^2T^{-2}$

$B$. Pascal $2$. $M^0L^0T^{-1}$

$C$. Hertz $3$. $M^1L^0T^{-2}$

$D$. Joule $4$. $M^1L^{-1}T^{-2}$

If the unit of length and force be increased four times,then the unit of energy is

Give an example of:
$(a)$ a physical quantity which has a unit but no dimensions
$(b)$ a physical quantity which has neither unit nor dimensions
$(c)$ a constant which has a unit
$(d)$ a constant which has no unit

The pair of physical quantities not having the same dimensions is:

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