In the depression of freezing point experiment:
$A.$ Vapour pressure of the solution is less than that of pure solvent
$B.$ Vapour pressure of the solution is more than that of pure solvent
$C.$ Only solute molecules solidify at the freezing point
$D.$ Only solvent molecules solidify at the freezing point

  • A
    $A$ and $D$ only
  • B
    $B$ and $C$ only
  • C
    $A$ and $C$ only
  • D
    $A$ only

Explore More

Similar Questions

After adding a non-volatile solute, the freezing point of water decreases to $-0.186^{\circ} C$. Calculate $\Delta T_b$ if $K_f = 1.86 \text{ K kg mol}^{-1}$ and $K_b = 0.521 \text{ K kg mol}^{-1}$. (in $\text{ K}$)

Column-$I$ (Various solutions)Column-$II$ (Their freezing point)
$a$. $0.1 \ M \ BaCl_2$ solution$p$. $271 \ K$
$b$. $0.1 \ M \ NaCl$ solution$q$. $270 \ K$
$c$. $0.1 \ M \ K_3[Fe(CN)_6]$ solution$s$. $269 \ K$
$d$. $0.1 \ M \ Al_2(SO_4)_3$ solution$r$. $268 \ K$
Given: Freezing point of $0.1 \ M$ sucrose solution $= 272 \ K$ and Freezing point of water $= 273 \ K$. Assume molarity $=$ molality. Which of the following options shows the correct matches?

Which of the following mixtures is known as Proof Spirit (by volume)?

Which one of the following statements is $FALSE$?

The values of $K_b$ and $K_f$ for water are $0.52 \, K \, kg \, mol^{-1}$ and $1.86 \, K \, kg \, mol^{-1}$ respectively. If the solution boils at $0.78 \, K$ above the boiling point of water,then the freezing point of the solution will be ........ $K$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo