In the figure, a potential of +1200 , V is ap | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The circuit consists of a $3 \, \mu F$ capacitor in series with a parallel combination of $4 \, \mu F$ and $2 \, \mu F$ capacitors.First, calculat

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(C) The circuit consists of a $3 \, \mu F$ capacitor in series with a parallel combination of $4 \, \mu F$ and $2 \, \mu F$ capacitors.First, calculate the equivalent capacitance of the parallel combination between point $P$ and point $B$:$C_{PB} = 4 \, \mu F + 2 \, \mu F = 6 \, \mu F$.Now, the circuit simplifies to a $3 \, \mu F$ capacitor in series with a $6 \, \mu F$ capacitor connected between $A$ and $B$.Since the capacitors are in series, the charge $Q$ on each is the same. The potential difference $V$ across a capacitor is given by $V = Q/C$, so $V \propto 1/C$.The potential difference is distributed in the inverse ratio of the capacitances:$V_{AP} / V_{PB} = C_{PB} / C_{AP} = 6 \, \mu F / 3 \, \mu F = 2/1$.Given the total potential difference $V_{AB} = 1200 \, V$, we have $V_{AP} + V_{PB} = 1200 \, V$.Substituting $V_{AP} = 2 V_{PB}$ into the equation:$2 V_{PB} + V_{PB} = 1200 \, V$$3 V_{PB} = 1200 \, V$$V_{PB} = 400 \, V$.Since point $B$ is earthed, its potential is $0 \, V$. Therefore, the potential at point $P$ is $V_P - V_B = 400 \, V$, which means $V_P = 400 \, V$.

In the figure, a potential of $+1200 \, V$ is applied to point $A$ and point $B$ is earthed. What is the potential at point $P$ (in $V$)?

Similar Questions

$A$ narrow parallel beam of light is incident paraxially on a solid transparent sphere of radius $r$ kept in air. What should be the refractive index if the beam is to be focused at the farther surface of the sphere?

$\left|\begin{array}{ccc}x+2 & x+3 & x+5 \\ x+4 & x+6 & x+9 \\ x+8 & x+11 & x+15\end{array}\right|$ is equal to

The product obtained at the anode when $50 \%$ $H_2SO_4$ aqueous solution is electrolysed using platinum electrodes is:

The given graph represents $V-I$ characteristic for a semiconductor device. Which of the following statements is correct?

The equation of the hyperbola whose directrix is $2x + y = 1$,focus is $(1, 1)$,and eccentricity $e = \sqrt{3}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module