In the figure, a potential of + 1200 , V is a | vedclass

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(C) The given circuit consists of a $3 \, \mu F$ capacitor in series with a parallel combination of $4 \, \mu F$ and $2 \, \mu F$ capacitors.First, ca

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$400$

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(C) The given circuit consists of a $3 \, \mu F$ capacitor in series with a parallel combination of $4 \, \mu F$ and $2 \, \mu F$ capacitors.First, calculate the equivalent capacitance of the parallel combination of $4 \, \mu F$ and $2 \, \mu F$ capacitors:$C_{eq} = 4 \, \mu F + 2 \, \mu F = 6 \, \mu F$.Now, the circuit is reduced to a series combination of a $3 \, \mu F$ capacitor and a $6 \, \mu F$ capacitor connected between $A$ and $B$.Since they are in series, the charge $Q$ on each capacitor is the same.Using the formula $Q = C V$, where $V$ is the potential difference across the capacitor:$Q = C_1 (V_A - V_P) = C_{eq} (V_P - V_B)$.Given $V_A = 1200 \, V$, $V_B = 0 \, V$, $C_1 = 3 \, \mu F$, and $C_{eq} = 6 \, \mu F$:$3 	imes (1200 - V_P) = 6 	imes (V_P - 0)$.$1200 - V_P = 2 V_P$.$3 V_P = 1200$.$V_P = 400 \, V$.

In the figure, a potential of $+ 1200 \, V$ is applied to point $A$ and point $B$ is earthed. What is the potential at point $P$ in volts?

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