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(D) According to Newton's third law,action and reaction forces always act on different bodies and are equal in magnitude and opposite in direction.$1$

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$\vec {F_4}$ and gravitational force exerted by balloon on earth are action-reaction pairs.

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(D) According to Newton's third law,action and reaction forces always act on different bodies and are equal in magnitude and opposite in direction.$1$. $\vec F_4$ represents the weight of the balloon,which is the gravitational force exerted by the Earth on the balloon. The reaction to this force is the gravitational force exerted by the balloon on the Earth,which acts on the Earth.$2$. Therefore,$\vec F_4$ and the gravitational force exerted by the balloon on the Earth form an action-reaction pair.$3$. Other options are incorrect because $\vec F_1, \vec F_2, \vec F_3$ are contact forces acting on the same body (the balloon) and do not form action-reaction pairs with each other.

In the figure shown,a balloon is pressed against a wall. It is in equilibrium and maximum compressed state. $\vec F_1 =$ force of balloon on hand of man; $\vec F_2 =$ force of balloon on wall; $\vec F_3 =$ friction; $\vec F_4 =$ weight of balloon. Choose the correct statement.

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