(C) The limiting friction force ${F_l}$ required to start the motion of the block is given by ${F_l} = {\mu _s}R$,where $R$ is the normal reaction for

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(C) The limiting friction force ${F_l}$ required to start the motion of the block is given by ${F_l} = {\mu _s}R$,where $R$ is the normal reaction force.Since the block is on a horizontal surface,$R = mg = 10 \, N$.Therefore,${F_l} = 0.4 \times 10 \, N = 4 \, N$.This means a minimum force of $4 \, N$ is required to overcome static friction and initiate motion.The applied horizontal force is $3 \, N$.Since the applied force $(3 \, N)$ is less than the limiting friction $(4 \, N)$,the block will not move.Thus,the correct option is $(C)$.

Class 11 Physics Newton's Laws of Motion and Friction Static and Limiting Friction and Minimum Force Required to Move

Easy

In the figure shown,a block of weight $10 \, N$ is resting on a horizontal surface. The coefficient of static friction between the block and the surface is ${\mu _s} = 0.4$. $A$ force of $3.5 \, N$ will keep the block in uniform motion,once it has been set in motion. If a horizontal force of $3 \, N$ is applied to the block,then the block will:

A
Move over the surface with constant velocity
B
Move having accelerated motion over the surface
C
Not move
D
First it will move with a constant velocity for some time and then will have accelerated motion

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Class 11 Questions

Class 11

Physics Questions

Chapter

Newton's Laws of Motion and Friction

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Static and Limiting Friction and Minimum Force Required to Move

$A$ wooden block of mass $M$ lies on a rough floor. Another wooden block of the same mass is hanging from the point $O$ through strings as shown in the figure. To achieve equilibrium,the coefficient of static friction between the block on the floor and the floor itself is:

MediumKCET 2025

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If a pushing force making an angle $\alpha$ with the horizontal is applied on a block of mass $m$ placed on a horizontal table and the angle of friction is $\beta$,then the minimum magnitude of the force required to move the block is

Difficult

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Block $B$ lying on a table weighs $W$. The coefficient of static friction between the block and the table is $\mu$. Assume that the cord between $B$ and the knot is horizontal. The maximum weight of the block $A$ for which the system will be stationary is

MediumWBJEE 2015

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$A$ block of mass $2\,kg$ is at rest on a floor. The coefficient of static friction between the block and the floor is $0.54$. $A$ horizontal force of $2.8\,N$ is applied to the block. What will be the frictional force between the block and the floor (in $.8$)? $(g = 10\,m/s^2)$

Medium

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As shown in the figure, a block of mass $10 \ kg$ lying on a horizontal surface is pulled by a force $F$ acting at an angle $30^{\circ}$ with the horizontal. For $\mu_{s} = 0.25$, the block will just start to move for the value of $F$: [Given $g = 10 \ ms^{-2}$] (in $N$)

DifficultWBJEE 2024

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$A$ wooden block of mass $M$ lies on a rough floor. Another wooden block of the same mass is hanging from the point $O$ through strings as shown in the figure. To achieve equilibrium,the coefficient of static friction between the block on the floor and the floor itself is:

If a pushing force making an angle $\alpha$ with the horizontal is applied on a block of mass $m$ placed on a horizontal table and the angle of friction is $\beta$,then the minimum magnitude of the force required to move the block is

Block $B$ lying on a table weighs $W$. The coefficient of static friction between the block and the table is $\mu$. Assume that the cord between $B$ and the knot is horizontal. The maximum weight of the block $A$ for which the system will be stationary is

$A$ block of mass $2\,kg$ is at rest on a floor. The coefficient of static friction between the block and the floor is $0.54$. $A$ horizontal force of $2.8\,N$ is applied to the block. What will be the frictional force between the block and the floor (in $.8$)? $(g = 10\,m/s^2)$

As shown in the figure, a block of mass $10 \ kg$ lying on a horizontal surface is pulled by a force $F$ acting at an angle $30^{\circ}$ with the horizontal. For $\mu_{s} = 0.25$, the block will just start to move for the value of $F$: [Given $g = 10 \ ms^{-2}$] (in $N$)

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