In the figure,the charge Q is at the centre o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The work done in moving a charge $q$ from a point $A$ to $B$ in an electric field is given by $W = q(V_B - V_A)$,where $V_A$ and $V_B$ are the ele

Vedclass · Accepted Answer

$K$

Vedclass · Answer

(A) The work done in moving a charge $q$ from a point $A$ to $B$ in an electric field is given by $W = q(V_B - V_A)$,where $V_A$ and $V_B$ are the electric potentials at points $A$ and $B$ respectively.Since the charge $Q$ is at the centre of the circle,all points on the circumference of the circle $(P, L, M, N)$ are at the same distance from $Q$. Therefore,they are at the same electric potential.Moving a charge between any two points on the circumference ($P$ to $L$,$P$ to $M$,or $P$ to $N$) results in zero work done because the potential difference is zero.Point $K$ is outside the circle,meaning it is at a different potential than point $P$. Moving a charge from $P$ to $K$ involves a change in potential,resulting in non-zero work done. Thus,the work done is maximum when moving the charge to $K$.

In the figure,the charge $Q$ is at the centre of the circle. Work done is maximum when another charge is taken from point $P$ to:

Similar Questions

Draw an equipotential surface for an electric dipole.

$A$ charge $Q$ is placed at the centre of a circle of radius $10 \ cm$. Find the work done in moving a charge $q$ between any two points lying on the arc of the circle.

$S_1$ and $S_2$ are two equipotential surfaces on which the potentials are not equal. Which of the following statements is incorrect?

Equipotential surfaces are given as shown. The electric field intensity is ........

Electric field is always ...... to the equipotential surface at every point. (Fill in the gap)

Vedclass Test Series

Exam Paper Generator

Online Exam Module