In the final answer of the expression frac{(2 | vedclass

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(B) Step $1$: Perform the subtraction in the numerator: $(29.2 - 20.2) = 9.0$. Since the subtraction rule states that the result should have the same

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$2$

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(B) Step $1$: Perform the subtraction in the numerator: $(29.2 - 20.2) = 9.0$. Since the subtraction rule states that the result should have the same number of decimal places as the term with the fewest decimal places,$9.0$ has $1$ decimal place (two significant figures). Step $2$: The expression becomes $\frac{9.0 	imes 1.79 	imes 10^5}{1.37}$. Step $3$: According to the multiplication and division rule,the final result should have the same number of significant figures as the term with the fewest significant figures. Here,$9.0$ has $2$ significant figures,$1.79$ has $3$ significant figures,and $1.37$ has $3$ significant figures. Therefore,the final answer must have $2$ significant figures.

In the final answer of the expression $\frac{(29.2 - 20.2)(1.79 \times 10^5)}{1.37}$,the number of significant figures is

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