In the first excited state of a hydrogen atom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a hydrogen atom, the radius of the $n^{th}$ orbit is given by the formula $r_n = a_0 	imes n^2$, where $a_0 = 0.529 	ext{ Å}$ is the Bohr ra

Vedclass · Accepted Answer

$2.1 	imes 10^{-10} 	ext{ m}$

Vedclass · Answer

(B) For a hydrogen atom, the radius of the $n^{th}$ orbit is given by the formula $r_n = a_0 	imes n^2$, where $a_0 = 0.529 	ext{ Å}$ is the Bohr radius.For the first excited state, the principal quantum number is $n = 2$.Substituting the value of $n$ into the formula, we get $r_2 = 0.529 	imes (2)^2 	ext{ Å}$.$r_2 = 0.529 	imes 4 	ext{ Å} = 2.116 	ext{ Å}$.Since $1 	ext{ Å} = 10^{-10} 	ext{ m}$, we have $r_2 = 2.116 	imes 10^{-10} 	ext{ m}$.Rounding to two significant figures, the radial distance is approximately $2.1 	imes 10^{-10} 	ext{ m}$.

Similar Questions

Line spectrum was first of all theoretically explained by

Let $r, v, E$ be the radius of orbit, speed of electron, and total energy of electron respectively in a $H$-atom. Which of the following quantities, according to Bohr theory, is proportional to the quantum number $n$?

Explain the limitations of the Bohr atomic model.

In a hydrogen atom,the radius of the $n^{th}$ Bohr orbit is $r_n$. The graph between $\log \left( \frac{r_n}{r_1} \right)$ and $\log n$ will be:

According to Bohr's theory,the angular momentum of an electron revolving in the second orbit of a hydrogen atom will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module