In the following acid-base reactions,in which | vedclass

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(D) An acid-base reaction always proceeds in the direction of the formation of a weaker acid and a weaker base. In option $A$,$EtO^-$ is a stronger ba

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$C_{10}H_7O^{-} + CH_3OH \rightleftharpoons C_{10}H_7OH + CH_3O^{-}$

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(D) An acid-base reaction always proceeds in the direction of the formation of a weaker acid and a weaker base. In option $A$,$EtO^-$ is a stronger base than $C_6H_5O^-$ and $C_6H_5OH$ is a stronger acid than $EtOH$,so the forward reaction is favoured. In option $B$,$KH$ is a very strong base,so the forward reaction is favoured. In option $C$,$Me_3CO^-$ is a stronger base than $OH^-$,so the forward reaction is favoured. In option $D$,$CH_3O^-$ is a stronger base than $C_{10}H_7O^-$ (naphthoxide ion),and $C_{10}H_7OH$ (naphthol) is a stronger acid than $CH_3OH$. Therefore,the equilibrium lies to the left,meaning the backward reaction is favoured.

Acid	$K_a$
$HCN$	$6.2 \times 10^{-10}$
$HF$	$7.2 \times 10^{-4}$
$HNO_2$	$4.0 \times 10^{-4}$

In the following acid-base reactions,in which case can the backward reaction be favoured?

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