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(B) In the given circuit,the Zener diode is connected in parallel with the $1\,k\Omega$ resistor. The Zener diode acts as a voltage regulator,maintain

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$5$

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(B) In the given circuit,the Zener diode is connected in parallel with the $1\,k\Omega$ resistor. The Zener diode acts as a voltage regulator,maintaining a constant voltage of $5\,V$ across it.Since the $1\,k\Omega$ resistor is in parallel with the Zener diode,the voltage across the $1\,k\Omega$ resistor is also $5\,V$.Using Ohm's law,the current $I$ flowing through the $1\,k\Omega$ resistor is given by:$I = \frac{V}{R} = \frac{5\,V}{1\,k\Omega} = \frac{5}{1 	imes 10^3\,\Omega} = 5 	imes 10^{-3}\,A = 5\,mA$.

In the following circuit,the current flowing through the $1\,k\Omega$ resistor is......$mA$.

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