In the following nuclear reaction,D xrightarr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The initial nucleus $D$ has mass number $A = 182$ and atomic number $Z = 74$.$1$. Alpha decay $(\alpha)$: Mass number decreases by $4$, atomic num

Vedclass · Accepted Answer

$174$ and $71$

Vedclass · Answer

(A) The initial nucleus $D$ has mass number $A = 182$ and atomic number $Z = 74$.$1$. Alpha decay $(\alpha)$: Mass number decreases by $4$, atomic number decreases by $2$.$2$. Beta decay $(\beta^-)$: Mass number remains unchanged, atomic number increases by $1$.$3$. Gamma decay $(\gamma)$: Mass number and atomic number remain unchanged.Calculation for mass number $(A)$:$A_{final} = 182 - 4 (	ext{first } \alpha) - 4 (	ext{second } \alpha) = 182 - 8 = 174$.Calculation for atomic number $(Z)$:$Z_{final} = 74 - 2 (	ext{first } \alpha) + 1 (\beta^-) - 2 (	ext{second } \alpha) = 74 - 4 + 1 = 71$.Thus, the mass number is $174$ and the atomic number is $71$.

In the following nuclear reaction,$D \xrightarrow{\alpha} D_{1} \xrightarrow{\beta^-} D_{2} \xrightarrow{\alpha} D_{3} \xrightarrow{\gamma} D_{4}$. The mass number of $D$ is $182$ and the atomic number is $74$. The mass number and atomic number of $D_{4}$ respectively will be:

Similar Questions

$A$ radioactive nucleus with $Z$ protons and $N$ neutrons emits an $\alpha$-particle,$2\beta^-$-particles,and $2$ gamma rays. The number of protons and neutrons in the nucleus left after the decay,respectively,are:

The electron emitted in beta radiation originates from

$A$ radioactive nucleus (initial mass number $A$ and atomic number $Z$) emits $3$ $\alpha$-particles and $2$ positrons. The ratio of the number of neutrons to that of protons in the final nucleus will be:

The end product of the decay of $ { }_{90} Th^{232} $ is $ { }_{82} Pb^{208} $. The number of $ \alpha $ and $ \beta $ particles emitted are respectively:

The nucleus ${ }_{88}^{226} Ra$ is converted into ${ }_{82}^{206} Pb$ by the emission of alpha $(\alpha)$ and beta $(\beta)$ particles. The number of alpha and beta particles emitted are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module