In the following number series, only one numb | vedclass

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(C) The pattern followed in the series is: $(n 	imes 	ext{position}) + (	ext{position} + 1)$.$4 	imes 1 + 2 = 6$$6 	imes 2 + 3 = 15$ (which is no

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$18$

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(C) The pattern followed in the series is: $(n 	imes 	ext{position}) + (	ext{position} + 1)$.$4 	imes 1 + 2 = 6$$6 	imes 2 + 3 = 15$ (which is not $18$)$15 	imes 3 + 4 = 49$$49 	imes 4 + 5 = 201$$201 	imes 5 + 6 = 1011$Since $15$ should be in the place of $18$, the wrong number is $18$.

In the following number series, only one number is wrong. Find out the wrong number.
$4, 6, 18, 49, 201, 1011$

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In the following number series, only one number is wrong. Find out the wrong number.$4, 6, 18, 49, 201, 1011$