In the following reaction,4P + 3KOH + 3H_2O t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the reaction $4P + 3KOH + 3H_2O 	o 3KH_2PO_2 + PH_3$,the oxidation state of $P$ changes as follows:$1$. In elemental phosphorus $(P_4)$,the ox

Vedclass · Accepted Answer

$P$ is oxidized as well as reduced

Vedclass · Answer

(A) In the reaction $4P + 3KOH + 3H_2O 	o 3KH_2PO_2 + PH_3$,the oxidation state of $P$ changes as follows:$1$. In elemental phosphorus $(P_4)$,the oxidation state of $P$ is $0$.$2$. In $KH_2PO_2$,the oxidation state of $P$ is calculated as: $1 + 2(+1) + x + 2(-2) = 0 \implies 1 + 2 + x - 4 = 0 \implies x = +1$.$3$. In $PH_3$,the oxidation state of $P$ is calculated as: $x + 3(+1) = 0 \implies x = -3$.Since the oxidation state of $P$ increases from $0$ to $+1$ (oxidation) and decreases from $0$ to $-3$ (reduction),$P$ is both oxidized and reduced. This is a disproportionation reaction.

In the following reaction,$4P + 3KOH + 3H_2O \to 3KH_2PO_2 + PH_3$,what happens to phosphorus $(P)$?

Similar Questions

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca(OH)_2 + Cl_2 \longrightarrow CaOCl_2 + H_2O$

What will $1 \ mol$ of $MnO_4^{2-}$ produce upon disproportionation in a neutral aqueous medium?

$Cu^{+}$ ion is not stable in aqueous solution due to:

$P_4 + 3KOH + 3H_2O \to PH_3 + 3KH_2PO_2$; In this reaction,phosphorus undergoes:

In the following reaction,assign the oxidation state for the underlined atom in the products of complete hydrolysis at $R.T.$:
$H_2\underline{S}_2O_6 + H_2O \longrightarrow H_2SO_3 + H_2SO_4$

Vedclass Test Series

Exam Paper Generator

Online Exam Module