In the following nuclear reaction,identify x: | vedclass

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(D) In the given nuclear reaction,the mass number remains constant at $64$ on both sides.For the atomic number,the reactant has $29$ and the product $

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$A$ positron

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(D) In the given nuclear reaction,the mass number remains constant at $64$ on both sides.For the atomic number,the reactant has $29$ and the product $Ni$ has $28$.To balance the atomic number,$x$ must have an atomic number of $29 - 28 = +1$.Thus,$x$ is a positron,represented as $_{1}e^{0}$ or $\beta^+$.The reaction is: $_{29}Cu^{64} 	o _{28}Ni^{64} + _{+1}e^{0}$.

In the following nuclear reaction,identify $x$: $_{29}Cu^{64} \to _{28}Ni^{64} + x$

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