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(A) The reaction is the Reimer-Tiemann reaction. $p$-cresol reacts with $CHCl_3$ and $OH^-$ to form an intermediate dichloromethyl cyclohexadienone de

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$B, D$

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(A) The reaction is the Reimer-Tiemann reaction. $p$-cresol reacts with $CHCl_3$ and $OH^-$ to form an intermediate dichloromethyl cyclohexadienone derivative. $1$. The phenoxide ion attacks the dichlorocarbene $(:CCl_2)$ generated from $CHCl_3$. $2$. This leads to the formation of a cyclohexadienone intermediate ($Q$ and $R$ are related to these intermediates). $3$. Hydrolysis and subsequent rearrangement lead to the formation of the major product $S$ ($2$-hydroxy$-5-$methylbenzaldehyde). $4$. Some side products like $Q$ ($4$-methyl$-4-$dichloromethyl-cyclohexa$-2,5-$dienone) are also formed as minor products during the reaction process. Thus,the major product is $S$ and the minor product is $Q$.

In the following Reimer-Tiemann reaction,the product$(s)$ formed is(are):
$p$-cresol + $CHCl_3$ + $OH^-$ $\rightarrow$ ?

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In the following Reimer-Tiemann reaction,the product$(s)$ formed is(are):$p$-cresol + $CHCl_3$ + $OH^-$ $\rightarrow$ ?