In the following reaction,the major product X | vedclass

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(A) The reaction proceeds in two steps:Step $1$: Ozonolysis of $1,2$-dimethylcyclopentene followed by reductive workup $(Zn/H_2O)$ leads to the format

Vedclass · Accepted Answer

$3-$methylcyclohex$-2-$en$-1-$one

Vedclass · Answer

(A) The reaction proceeds in two steps:Step $1$: Ozonolysis of $1,2$-dimethylcyclopentene followed by reductive workup $(Zn/H_2O)$ leads to the formation of heptane-$2,6$-dione.Step $2$: The resulting heptane-$2,6$-dione undergoes an intramolecular aldol condensation in the presence of base $(OH^-)$. The enolate formed at the $\alpha$-carbon attacks the other carbonyl group to form a $\beta$-hydroxy ketone intermediate. This intermediate subsequently undergoes dehydration (loss of $H_2O$) to form the stable $\alpha,\beta$-unsaturated carbonyl compound,which is $3$-methylcyclohex-$2$-en-$1$-one.

In the following reaction,the major product $X$ is

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