In the following reaction sequence,X and Y,re | vedclass

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(B) The reaction sequence involves the conversion of an alkene to an epoxide followed by the reduction of the epoxide to an alcohol.$1$. The conversio

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$C_6H_5COOH$; $LiAlH_4$

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(B) The reaction sequence involves the conversion of an alkene to an epoxide followed by the reduction of the epoxide to an alcohol.$1$. The conversion of an alkene to an epoxide (epoxidation) requires a peroxyacid. $C_6H_5COOH$ (perbenzoic acid) is a standard reagent for this transformation.$2$. The reduction of an epoxide to an alcohol requires a strong reducing agent like $LiAlH_4$,which attacks the less hindered carbon of the epoxide ring to yield the corresponding alcohol.Therefore,$X = C_6H_5COOH$ and $Y = LiAlH_4$.

In the following reaction sequence,$X$ and $Y$,respectively,are:
$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$

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In the following reaction sequence,$X$ and $Y$,respectively,are:$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$