In the following reaction,assign the correct option for the underlined atom in the product of complete hydrolysis at $R.T.$:
$\underline{N}_2O_3 + H_2O \longrightarrow 2HNO_2$
$\underline{N}_2O_3 + H_2O \longrightarrow 2HNO_2$
- AIf product is oxy acid with $-ic$ suffix
- BIf product is oxy acid with $-ous$ suffix
- CIf product are two oxy acids one with $-ic$ suffix and other one with $-ous$ suffix.
- DIf product is not oxy acid,neither with $-ic$ suffix nor with $-ous$ suffix.
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Similar Questions
Nitrogen is a relatively inactive element because
Which of the following, when subjected to thermal decomposition, will liberate dinitrogen?
$(i)$ Sodium nitrate
$(ii)$ Ammonium dichromate
$(iii)$ Barium azide
$(i)$ Sodium nitrate
$(ii)$ Ammonium dichromate
$(iii)$ Barium azide
Which of the following halides is most acidic?
Medium
View SolutionThe oxoacid of phosphorus having the strongest reducing property is
The correct code for stability of oxidation states for given cations is:
$(i)$ $Pb^{2+} > Pb^{4+}, Tl^{+} < Tl^{3+}$
$(ii)$ $Bi^{3+} < Sb^{3+}, Sn^{2+} < Sn^{4+}$
$(iii)$ $Pb^{2+} > Pb^{4+}, Bi^{3+} > Bi^{5+}$
$(iv)$ $Tl^{3+} < In^{3+}, Sn^{2+} > Sn^{4+}$
$(v)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} > Pb^{4+}$
$(vi)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} < Pb^{4+}$
$(i)$ $Pb^{2+} > Pb^{4+}, Tl^{+} < Tl^{3+}$
$(ii)$ $Bi^{3+} < Sb^{3+}, Sn^{2+} < Sn^{4+}$
$(iii)$ $Pb^{2+} > Pb^{4+}, Bi^{3+} > Bi^{5+}$
$(iv)$ $Tl^{3+} < In^{3+}, Sn^{2+} > Sn^{4+}$
$(v)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} > Pb^{4+}$
$(vi)$ $Sn^{2+} < Pb^{2+}, Sn^{4+} < Pb^{4+}$
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