In the following reaction,assign the correct category for the underlined atom based on the product of complete hydrolysis at $R.T.$:
$\underline{S}O_2Cl_2 + H_2O \longrightarrow H_2SO_4 + HCl$
$\underline{S}O_2Cl_2 + H_2O \longrightarrow H_2SO_4 + HCl$
- AIf product is oxy acid with $-ic$ suffix
- BIf product is oxy acid with $-ous$ suffix
- CIf product are two oxy acids,one with $-ic$ suffix and other one with $-ous$ suffix
- DIf product is not an oxy acid,neither with $-ic$ suffix nor with $-ous$ suffix
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The correct formula of permanganic acid is
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View SolutionMatch the following compounds with the oxidation number of the central atom (or specific atom in question):
Compound Oxidation number $1$. $C_6H_{12}O_6$ (Carbon) $a$. $+1$ $2$. $CCl_4$ (Carbon) $b$. $0$ $3$. $NH_4Cl$ (Nitrogen) $c$. $+4$ $4$. $Ba(H_2PO_2)_2$ (Phosphorus) $d$. $-3$
| Compound | Oxidation number |
| $1$. $C_6H_{12}O_6$ (Carbon) | $a$. $+1$ |
| $2$. $CCl_4$ (Carbon) | $b$. $0$ |
| $3$. $NH_4Cl$ (Nitrogen) | $c$. $+4$ |
| $4$. $Ba(H_2PO_2)_2$ (Phosphorus) | $d$. $-3$ |
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View SolutionIf a metal ion $M^{3+}$ loses three more electrons,what will be its final oxidation number?
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View SolutionAssign the oxidation number to the underlined element in each of the following species:
$1$. $NaH_{2}\underline{P}O_{4}$
$2$. $NaH\underline{S}O_{4}$
$3$. $H_{4}\underline{P_{2}}O_{7}$
$1$. $NaH_{2}\underline{P}O_{4}$
$2$. $NaH\underline{S}O_{4}$
$3$. $H_{4}\underline{P_{2}}O_{7}$
Medium
View SolutionWhat are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?
$(a)$ $K\underline {I_3}$
$(b)$ $H_2\underline {S_4}O_6$
$(c)$ $\underline {Fe_3}O_4$
$(d)$ $\underline {C}H_3\underline {C}H_2OH$
$(e)$ $\underline {C}H_3\underline {C}OOH$
$(a)$ $K\underline {I_3}$
$(b)$ $H_2\underline {S_4}O_6$
$(c)$ $\underline {Fe_3}O_4$
$(d)$ $\underline {C}H_3\underline {C}H_2OH$
$(e)$ $\underline {C}H_3\underline {C}OOH$
Medium
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