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(A) is ethyne $(C_2H_2)$.Cyclic trimerization of ethyne over red hot $Cu$ tube gives $B$,which is benzene $(C_6H_6)$.Friedel-Crafts alkylation of benz

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$13$

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(A) is ethyne $(C_2H_2)$.Cyclic trimerization of ethyne over red hot $Cu$ tube gives $B$,which is benzene $(C_6H_6)$.Friedel-Crafts alkylation of benzene with $CH_3Cl$ in the presence of anhydrous $AlCl_3$ gives $C$,which is toluene $(C_6H_5CH_3)$.In toluene,the benzene ring is planar. The carbon atom of the methyl group is $sp^3$ hybridized,meaning the three hydrogen atoms of the methyl group are not in the same plane as the benzene ring.However,one hydrogen atom of the methyl group can rotate into the plane of the benzene ring.Thus,the atoms in the same plane are: $6$ carbons of the ring,$5$ hydrogens of the ring,$1$ carbon of the methyl group,and $1$ hydrogen of the methyl group.Total atoms in one plane = $6 + 5 + 1 + 1 = 13$.

In the following sequence of reactions,the maximum number of atoms present in molecule $C$ in one plane is:
$A$ $\xrightarrow[Cu \text{ tube}]{\text{Red hot}} B$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl (1 \text{ eq})} C$
($A$ is the lowest molecular weight alkyne)

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In the following sequence of reactions,the maximum number of atoms present in molecule $C$ in one plane is:$A$ $\xrightarrow[Cu \text{ tube}]{\text{Red hot}} B$ $\xrightarrow[\text{Anhydrous } AlCl_3]{CH_3Cl (1 \text{ eq})} C$($A$ is the lowest molecular weight alkyne)