In the following species, the one which is li | vedclass

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Question

(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin

Vedclass · Accepted Answer

$Ph-C^-(OH)(CN)$

Vedclass · Answer

(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin. The mechanism begins with the nucleophilic attack of $CN^-$ on the carbonyl carbon of benzaldehyde. This is followed by a proton transfer (tautomerization) to form a carbanion intermediate, which is stabilized by the electron-withdrawing $CN$ group and the phenyl ring. The structure of this key intermediate is $Ph-C^-(OH)(CN)$. This carbanion then attacks another molecule of benzaldehyde to continue the reaction, eventually leading to the formation of benzoin after the elimination of the $CN^-$ catalyst.

In the following species, the one which is likely to be the intermediate during benzoin condensation of benzaldehyde is

Similar Questions

Arrange the following carbocations in decreasing order of stability:
$I: CH_3-CH_2^+$
$II: (CH_3)_2CH^+$
$III: Ph-CH_2^+$

What is the hybridization state of a carbocation?

$:CCl_2$ is

Which carbocation is the least stable?

The decreasing order of stability of the following carbocations is:
$A$. $m-CH_3O-C_6H_4-CH_2^+$
$B$. $p-CH_3O-C_6H_4-CH_2^+$
$C$. $C_6H_5-CH_2^+$
$D$. $p-NO_2-C_6H_4-CH_2^+$

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