In the fusion reaction,${ }_1 H^2+{ }_1 H^2 \rightarrow{ }_2 He^4+Q$,where $Q$ is the energy released. If $c$ is the speed of light and $m$ is the mass of each deuterium nucleus,then the mass of the helium nucleus formed is:
- A$2m + \frac{Q}{c^2}$
- B$\frac{Q}{mc^2}$
- C$m + \frac{Q}{c^2}$
- D$2m - \frac{Q}{c^2}$
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