In the given (V-T) diagram,what is the relati | vedclass

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(B) According to the ideal gas equation,$PV = nRT$,which can be rewritten as $V = (nR/P)T$.For an isobaric process,the pressure $P$ is constant,and $V

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$P_2 < P_1$

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(B) According to the ideal gas equation,$PV = nRT$,which can be rewritten as $V = (nR/P)T$.For an isobaric process,the pressure $P$ is constant,and $V \propto T$.Therefore,the $(V-T)$ graph is a straight line passing through the origin,where the slope of the line is given by $m = nR/P$.Since the slope $m$ is inversely proportional to the pressure $P$ $(m \propto 1/P)$,a larger slope corresponds to a smaller pressure.From the given diagram,the angle $	heta_2 > 	heta_1$,which implies that the slope of the line for $P_2$ is greater than the slope of the line for $P_1$ (i.e.,$	ext{slope}_2 > 	ext{slope}_1$).Since the slope is inversely proportional to pressure,we conclude that $P_2 < P_1$.

In the given $(V-T)$ diagram,what is the relation between pressure $P_1$ and $P_2$?

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