In the given Cannizzaro reaction,the slowest | vedclass

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(B) The Cannizzaro reaction involves the nucleophilic attack of $OH^-$ on the carbonyl carbon to form a di-anion intermediate.This intermediate then u

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The transfer of hydride to the carbonyl group

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(B) The Cannizzaro reaction involves the nucleophilic attack of $OH^-$ on the carbonyl carbon to form a di-anion intermediate.This intermediate then undergoes a hydride transfer to another molecule of aldehyde.The hydride transfer step is the rate-determining step $(R.D.S.)$ because it involves the breaking of a $C-H$ bond and is the slowest step in the mechanism.

In the given Cannizzaro reaction,the slowest step is:
$2PhCHO \xrightarrow{KOH} PhCH_2OH + PhCOO^-$

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In the given Cannizzaro reaction,the slowest step is:$2PhCHO \xrightarrow{KOH} PhCH_2OH + PhCOO^-$