In the given circuit,calculate $(i)$ total resistance of the circuit,and (ii) current shown by the ammeter.

(N/A) $(i)$ Since $R_{1}$ and $R_{2}$ are in series,their resultant resistance,
$R_{S} = R_{1} + R_{2} = 3 + 2 = 5 \Omega$
Further,$R_{S}$ and $R_{3}$ are in parallel,their resultant resistance is given by
$R_{P} = \frac{R_{S} \times R_{3}}{R_{S} + R_{3}} = \frac{5 \times 5}{5 + 5} = 2.5 \Omega$
(ii) Also,the current $I$ shown by the ammeter is given by Ohm's law:
$I = \frac{V}{R_{P}} = \frac{2.5 \text{ V}}{2.5 \Omega} = 1 \text{ A}$