In the given circuit,the input voltage V_{tex | vedclass

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(D) The circuit consists of two diodes $D_{1}$ and $D_{2}$ connected in parallel with opposite polarities.$1$. During the positive half-cycle of $V_{\

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(D) The circuit consists of two diodes $D_{1}$ and $D_{2}$ connected in parallel with opposite polarities.$1$. During the positive half-cycle of $V_{	ext{in}}$:- When $V_{	ext{in}} - When $V_{	ext{in}} \geq 0.6\,V$,diode $D_{1}$ becomes forward-biased and conducts. The voltage across it is clamped to its cut-in voltage of $0.6\,V$. Thus,$V_{0} = 0.6\,V$.$2$. During the negative half-cycle of $V_{	ext{in}}$:- When $|V_{	ext{in}}| - When $|V_{	ext{in}}| \geq 0.6\,V$,diode $D_{2}$ becomes forward-biased and conducts. The voltage across it is clamped to $-0.6\,V$. Thus,$V_{0} = -0.6\,V$.Combining these,the output waveform is clipped at $+0.6\,V$ and $-0.6\,V$. This corresponds to the waveform shown in option $D$.

In the given circuit,the input voltage $V_{\text{in}}$ is shown in the figure. The cut-in voltage of the $p-n$ junction diode ($D_{1}$ or $D_{2}$) is $0.6\,V$. Which of the following output voltage $(V_{0})$ waveforms across the diode is correct?

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