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(B) In a series $LCR$ circuit,the voltage across the inductor is $V_L$ (reading of $V_1$) and the voltage across the capacitor is $V_C$ (reading of $V

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$220 \, V, 2.2 \, A$

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(B) In a series $LCR$ circuit,the voltage across the inductor is $V_L$ (reading of $V_1$) and the voltage across the capacitor is $V_C$ (reading of $V_2$).Given $V_L = V_C = 300 \, V$.Since $V_L = V_C$,the circuit is in resonance.At resonance,the net reactance $X = X_L - X_C = 0$,so the total impedance $Z = R = 100 \, \Omega$.The source voltage $V = 220 \, V$ is entirely dropped across the resistor $R$.Therefore,the reading of voltmeter $V_3$ is $V_R = V = 220 \, V$.The current in the circuit is $I = \frac{V}{Z} = \frac{220 \, V}{100 \, \Omega} = 2.2 \, A$.Thus,the reading of ammeter $A$ is $2.2 \, A$.

In the given circuit,the readings of voltmeters $V_1$ and $V_2$ are $300 \, V$ each. The readings of voltmeter $V_3$ and ammeter $A$ are respectively:

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