In the given figure,switches S_{1} and S_{2} | vedclass

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(C) When switches $S_{1}$ and $S_{2}$ are closed,the circuit simplifies into three parallel combinations connected in series.$1$. The first part consi

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$10$

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(C) When switches $S_{1}$ and $S_{2}$ are closed,the circuit simplifies into three parallel combinations connected in series.$1$. The first part consists of $12 \, \Omega$ and $6 \, \Omega$ resistors in parallel. The equivalent resistance is $R_{1} = \frac{12 	imes 6}{12 + 6} = \frac{72}{18} = 4 \, \Omega$.$2$. The middle part consists of $4 \, \Omega$ and $4 \, \Omega$ resistors in parallel. The equivalent resistance is $R_{2} = \frac{4 	imes 4}{4 + 4} = \frac{16}{8} = 2 \, \Omega$.$3$. The third part consists of $6 \, \Omega$ and $12 \, \Omega$ resistors in parallel. The equivalent resistance is $R_{3} = \frac{6 	imes 12}{6 + 12} = \frac{72}{18} = 4 \, \Omega$.Since these three combinations are in series,the total equivalent resistance is $R_{eq} = R_{1} + R_{2} + R_{3} = 4 + 2 + 4 = 10 \, \Omega$.

In the given figure,switches $S_{1}$ and $S_{2}$ are initially open. What is the equivalent resistance across $a b$ when the switches $S_{1}$ and $S_{2}$ are closed? (in $\Omega$)

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