In the given reaction:CH_3-CH_2-COOH xrightar | vedclass

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(A) The reaction described is the Hunsdiecker reaction,which involves the decarboxylation of the silver salt of a carboxylic acid in the presence of b

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Ethyl bromide

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(A) The reaction described is the Hunsdiecker reaction,which involves the decarboxylation of the silver salt of a carboxylic acid in the presence of bromine.Step $1$: $CH_3-CH_2-COOH + AgNO_3 \rightarrow CH_3-CH_2-COOAg + HNO_3$Step $2$: $CH_3-CH_2-COOAg + Br_2 \xrightarrow{\Delta} CH_3-CH_2-Br + CO_2 + AgBr$Thus,the product $[X]$ is ethyl bromide $(CH_3-CH_2-Br)$.

In the given reaction:
$CH_3-CH_2-COOH \xrightarrow[(ii) \ Br_2/\Delta]{(i) \ AgNO_3} [X]$
$[X]$ will be:

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In the given reaction:$CH_3-CH_2-COOH \xrightarrow[(ii) \ Br_2/\Delta]{(i) \ AgNO_3} [X]$$[X]$ will be: